56 lines
1.9 KiB
Plaintext
56 lines
1.9 KiB
Plaintext
= Best Practices
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Over time, a couple of best practices have emerged. The following list should serve as a guideline for developers writing embedded software in _Rust_, especially in the context of the _Embassy_ framework.
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== Passing Buffers by Reference
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It may be tempting to pass arrays or wrappers, like link:https://docs.rs/heapless/latest/heapless/[`heapless::Vec`],
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to a function or return one just like you would with a `std::Vec`. However, in most embedded applications you don't
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want to spend resources on an allocator and end up placing buffers on the stack. This, however, can easily blow up
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your stack if you are not careful.
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Consider the following example:
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[,rust]
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----
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fn process_buffer(mut buf: [u8; 1024]) -> [u8; 1024] {
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// do stuff and return new buffer
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for elem in buf.iter_mut() {
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*elem = 0;
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}
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buf
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}
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pub fn main() -> () {
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let buf = [1u8; 1024];
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let buf_new = process_buffer(buf);
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// do stuff with buf_new
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()
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}
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----
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When calling `process_buffer` in your program, a copy of the buffer you pass to the function will be created,
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consuming another 1024 bytes.
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After the processing, another 1024 byte buffer will be placed on the stack to be returned to the caller.
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(You can check the assembly, there will be two memcopy operations, e.g., `bl __aeabi_memcpy` when compiling for a Cortex-M processor.)
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*Possible Solution:*
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Pass the data by reference and not by value on both, the way in and the way out.
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For example, you could return a slice of the input buffer as the output.
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Requiring the lifetime of the input slice and the output slice to be the same, the memory safety of this procedure will be enforced by the compiler.
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[,rust]
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----
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fn process_buffer<'a>(buf: &'a mut [u8]) -> &'a mut[u8] {
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for elem in buf.iter_mut() {
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*elem = 0;
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}
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buf
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}
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pub fn main() -> () {
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let mut buf = [1u8; 1024];
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let buf_new = process_buffer(&mut buf);
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// do stuff with buf_new
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()
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}
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----
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